AP EAMCET · Chemistry · Chemical Equilibrium
In a reaction, \(A+B \rightleftharpoons C+D, 40 \%\) of \(B\) has reacted at equilibrium, when 1 mole of \(A\) was heated with 1 mole of \(B\) in a \(10 \mathrm{~L}\) closed vessel. The value of \(K_C\) is
- A \(0.44\)
- B \(0.18\)
- C \(0.22\)
- D \(0.36\)
Answer & Solution
Correct Answer
(A) \(0.44\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & A+B \rightleftharpoons C \quad+D \\ & \text { At } t=0,1 \quad 1 \quad 0 \quad 0 \\ & \text { At equil. }(1-0.4)(1-0.4) 0.40 .4 \\ & =0.6 \quad=0.6 \\ & K_c=\frac{[C][D]}{[A][B]} \\ & =\frac{0.4 \times 0.4}{0.6 \times 0.6}=0.44 \\ & \end{aligned}\)
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