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AP EAMCET · Chemistry · States of Matter

RMS velocity of one mole of an ideal gas was measured at different temperatures. A graph of \(\left(\mathrm{u}_{\mathrm{rms}}\right)^2\) (on y -axis) and \(\mathrm{T}(\mathrm{K})\) (on x -axis) gave straight line passing through the origin and its slope is \(249 \mathrm{~m}^2 \mathrm{~s}^{-2} \mathrm{~K}^{-1}\). What is the molar mass (in \(\left.\mathrm{kg} \mathrm{mol}^{-1}\right)\) of ideal gas? \(\left(\mathrm{R}=8.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)\)

  1. A \(10\)
  2. B \(1.0\)
  3. C \(24.9\)
  4. D \(1 \times 10^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(10\)

Step-by-step Solution

Detailed explanation

RMS velocity \(\left(v_{\text {rms }}\right)=\sqrt{\frac{3 R T}{M}}\) \(\begin{aligned} & v_{\mathrm{rms}}^2=\frac{3 \mathrm{RT}}{\mathrm{M}} \\ & \mathrm{y}=\mathrm{mx}+\mathrm{C}\end{aligned}\) where,…