AP EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
If the successive ionisation energies of an element \(A\) are 165, 190, 550 and \(595 \mathrm{kcal}\), respectively, then the ground state electronic configuration of element \(A\) is
- A \([\mathrm{Ne}] 3 s^2 3 p^2\)
- B \([\mathrm{He}] 2 \mathrm{~s}^1\)
- C \([\mathrm{He}] 2 s^2 2 p^2\)
- D \([\mathrm{Ne}] 3 \mathrm{~s}^2\)
Answer & Solution
Correct Answer
(D) \([\mathrm{Ne}] 3 \mathrm{~s}^2\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \mathrm{IE}_1=165 \mathrm{kcal}, \mathrm{IE}_2=190 \mathrm{kcal} . \\ & \mathrm{IE}_3=550 \mathrm{kcal}, \mathrm{IE}_4=595 \mathrm{kcal} \end{aligned} \] As ionisation energy value (first and second) of element \(A\) is lower, than third and fourth…
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