AP EAMCET · Chemistry · States of Matter
Pressure of \(1 \mathrm{~g}\) ideal gas \(X\) at \(300 \mathrm{~K}\) is \(2 \mathrm{~atm}\). When \(2 \mathrm{~g}\) of another gas \(Y\) is introduced in the same vessel at same temperature, the pressure become \(\mathrm{l}\) atm. The correct relationship between molar masses of \(X\) and \(Y\) is
- A \(M_Y=2 M_X\)
- B \(M_Y=4 M_X\)
- C \(M_x=4 M_y\)
- D \(M_X=5 M_Y\)
Answer & Solution
Correct Answer
(B) \(M_Y=4 M_X\)
Step-by-step Solution
Detailed explanation
Given, Initially, \(\begin{array}{ll}p=2 \mathrm{~atm}, & T=300 \mathrm{~K} \\ V=v \mathrm{~L}, & m_x=1 \mathrm{~g}\end{array}\) Finally, \(\begin{array}{rlrl}p & =2+1 & T & =300 \mathrm{~K} \\ & =3 \mathrm{~atm} & m_y & =2 \mathrm{~g}\end{array}\) \(\quad V=v \mathrm{~L}\) Let…
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