AP EAMCET · Chemistry · Structure of Atom
If the mass defect of a nuclide is \(3.32 \times 10^{-26} \mathrm{~g}\), its binding energy is \(\mathrm{MeV}\)
- A 9.31
- B 18.62
- C 27.93
- D 37.24
Answer & Solution
Correct Answer
(B) 18.62
Step-by-step Solution
Detailed explanation
Mass defect \(=3.32 \times 10^{-26} \mathrm{~g}\) \(=\frac{3.32 \times 10^{-26}}{1.66 \times 10^{-24}} \mathrm{amu}\) Binding energy \(=\) Mass defect \(\times 931 \mathrm{MeV}\) \(=\frac{3.32 \times 10^{-26}}{1.66 \times 10^{-24}} \times 931=18.62 \mathrm{MeV}\)
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