AP EAMCET · Chemistry · Amines
The \(\%\) of carbon in ' \(z\) ' is (At.wt. \(C=12 u, H=1 u, N=14 u, O=16 u\) )
- A \(71.3\)
- B \(51.3\)
- C \(61.3\)
- D \(48.3\)
Answer & Solution
Correct Answer
(C) \(61.3\)
Step-by-step Solution
Detailed explanation
Molecular Formula of 'z': \(C_7H_5O_3\) Molar Mass: \(M = 7(12) + 5(1) + 3(16) = 84 + 5 + 48 = 137 \text{ u}\) Mass of Carbon: \(C_{mass} = 7(12) = 84 \text{ u}\) Percentage of Carbon: \(\%C = \frac{84}{137} \times 100 = 61.313...\% \approx 61.3\%\)
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