AP EAMCET · Maths · Straight Lines
If the line \(p x-q y=r\) intersects the coordinate axes at \((a, 0)\) and \((0, b)\), then the value of \((a+b)\) is equal to
- A \(\frac{r(q+p)}{p q}\)
- B \(\frac{r(q-p)}{p q}\)
- C \(\frac{r(p-q)}{p q}\)
- D \(\frac{r(p-q)}{p+q}\)
Answer & Solution
Correct Answer
(B) \(\frac{r(q-p)}{p q}\)
Step-by-step Solution
Detailed explanation
We have, \(p x-q y=r\) intersect the coordinates axes at \((a, 0)\) and \((0, b)\). \(\therefore \quad p a=r \Rightarrow a=\frac{r}{p}\) \(0-b q=r \Rightarrow b=\frac{-r}{q}\) \(\therefore \quad a+b=\frac{r}{p}-\frac{r}{q}=\frac{r(q-p)}{p q}\)
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