AP EAMCET · Chemistry · Solid State
For \(\mathrm{NaCl}\), the number of Schottky pairs per \(\mathrm{cm}^3\) at room temperature is
- A \(10^{12}\)
- B \(10^{23}\)
- C \(10^{6}\)
- D \(10^{4}\)
Answer & Solution
Correct Answer
(C) \(10^{6}\)
Step-by-step Solution
Detailed explanation
For \(1 \mathrm{~cm}^3\) of \(\mathrm{NaCl}\), there are \(10^{22}\) ions, so there are \(10^{16}\) ions present per Schottky defect. Therefore, for each \(\mathrm{cm}^3\), there are \(10^6\) Schottky pairs at room temperature.
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