AP EAMCET · Chemistry · Haloalkanes and Haloarenes
The major products \(P\) and \(Q\) of the following reactions respectively are
I. \(n\)-pentyl bromide \(\xrightarrow{\mathrm{Zn} / \mathrm{H}^{+}} P\)
II. \(n\)-pentyl bromide \(\xrightarrow[\text { Dry ether }]{\mathrm{Na}} Q\)
- A pentane; decane
- B pent-1-en; decane
- C pentane ; pentane
- D pentane : 1-decene
Answer & Solution
Correct Answer
(A) pentane; decane
Step-by-step Solution
Detailed explanation
When \(n\)-pentyl bromide reacts with \(\mathrm{Zn}\), \(\mathrm{Br}\) atom is substituted by \(\mathrm{H}\)-atom to form pentane. But when \(n\)-pentyl bromide reacts with \(\mathrm{Na}\) and dry ether, it undergoes Wurtz reaction and decane is formed.
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