AP EAMCET · Chemistry · Structure of Atom
Electrons with a kinetic energy of \(6.023 \times 10^4 \mathrm{~J} / \mathrm{mol}\) are evolved from the surface of a metal, when it is exposed to radiation of wavelength of \(600 \mathrm{~nm}\). The minimum amount of energy required to remove an electron from the metal atom is
- A \(2.3125 \times 10^{-19} \mathrm{~J}\)
- B \(3 \times 10^{-19} \mathrm{~J}\)
- C \(6.02 \times 10^{-19} \mathrm{~J}\)
- D \(6.62 \times 10^{-34} \mathrm{~J}\)
Answer & Solution
Correct Answer
(A) \(2.3125 \times 10^{-19} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \because 1 \mathrm{~mol}=6.023 \times 10^{23} \text { atoms } \\ & \mathrm{KE} \text { of } 1 \mathrm{~mol}=6.023 \times 10^4 \mathrm{~J} \\ & \text { or KE of } 6.023 \times 10^{23} \text { atoms } \\ & =6.023 \times 10^4 \mathrm{~J} \\ & \therefore \quad…
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