AP EAMCET · Chemistry · Redox Reactions
From the given reaction
\(2 \mathrm{KMnO}_4 +3 \mathrm{H}_2 \mathrm{SO}_4+5 \mathrm{H}_2 \mathrm{O}_2 \longrightarrow \mathrm{K}_2 \mathrm{SO}_4+2 \mathrm{MnSO}_4 +8 \mathrm{H}_2 \mathrm{O}+5 \mathrm{O}_2\)
Find the normality of \(\mathrm{H}_2 \mathrm{O}_2\) solution, if \(20 \mathrm{~mL}\) of it is required to react completely with 16 \(\mathrm{mL}\) of \(0.02 \mathrm{M} \mathrm{KMnO}_4\) solution.
\(\left(\right.\) Molar mass of \(\mathrm{KMnO}_4=158 \mathrm{~g} \mathrm{~mol}^{-1}\) )
- A \(4 \times 10^{-2} \mathrm{~N}\)
- B \(2 \times 10^{-2} \mathrm{~N}\)
- C \(6 \times 10^{-2} \mathrm{~N}\)
- D \(8 \times 10^{-2} \mathrm{~N}\)
Answer & Solution
Correct Answer
(D) \(8 \times 10^{-2} \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Using law of equivalence Number of gram equivalence of \(\mathrm{H}_2 \mathrm{O}_2\) \(=\text { number of gram equivalence of } \mathrm{KMnO}_4\) Number of gram equivalence \(=\text { normality } \times \text { volume }(\text { in litres) }\) or normality \(=\) molarity…
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