AP EAMCET · Chemistry · d and f Block Elements
Correct order of basic strength of metallic hydroxides
- A \(\mathrm{Ce}(\mathrm{OH})_3 < \mathrm{Lu}(\mathrm{OH})_3 < \mathrm{Eu}(\mathrm{OH})_3\)
- B \(\mathrm{Ce}(\mathrm{OH})_3 < \mathrm{Eu}(\mathrm{OH})_3 < \mathrm{Lu}(\mathrm{OH})_3\)
- C \(\mathrm{Lu}(\mathrm{OH})_3 < \mathrm{Eu}(\mathrm{OH})_3 < \mathrm{Ce}(\mathrm{OH})_3\)
- D \(\mathrm{Lu}(\mathrm{OH})_3 < \mathrm{Ce}(\mathrm{OH})_3 < \mathrm{Eu}(\mathrm{OH})_3\)
Answer & Solution
Correct Answer
(C) \(\mathrm{Lu}(\mathrm{OH})_3 < \mathrm{Eu}(\mathrm{OH})_3 < \mathrm{Ce}(\mathrm{OH})_3\)
Step-by-step Solution
Detailed explanation
The atomic numbers of the given lanthanides are:- \(\mathrm{Ce}=58, \mathrm{Eu}=63, \mathrm{Lu}=71\) Since the metallic character decreases from left to right in a period, the order of metallic character for the given metal will be \(\mathrm{Lu} < \mathrm{Eu} < \mathrm{Ce}\).…
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