AP EAMCET · Chemistry · d and f Block Elements
Which of the following pair of transition metal ions, have the same calculated values of magnetic moment?
- A \(\mathrm{Ti}^{2+}\) and \(\mathrm{V}^{2+}\)
- B \(\mathrm{Fe}^{2+}\) and \(\mathrm{Cu}^{2+}\)
- C \(\mathrm{Cr}^{2+}\) and \(\mathrm{Fe}^{2+}\)
- D \(\mathrm{Co}^{2+}\) and \(\mathrm{Ti}^{2+}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{Cr}^{2+}\) and \(\mathrm{Fe}^{2+}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Cr}^{2+}(Z=24):[\mathrm{Ar}] 3 d^4 4 s^0 ; \quad 4 \quad\) unpaired electrons \(\quad \mathrm{Fe}^{2+}(Z=26):[\mathrm{Ar}] 3 d^6 4 s^0\); 4 unpaired electrons \(\mathrm{Cr}^{2+}\) and \(\mathrm{Fe}^{2+}\) have same number of unpaired electrons, hence they have the same…
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