AP EAMCET · Chemistry · s Block Elements
Consider the elements \(\mathrm{Ne}, \mathrm{Na}, \mathrm{Mg}\). The element with highest first ionization enthalpy and element with lowest second ionization enthalpy respectively are
- A \(\mathrm{Na}, \mathrm{Ne}\)
- B \(\mathrm{Ne}, \mathrm{Mg}\)
- C \(\mathrm{Na}, \mathrm{Na}\)
- D \(\mathrm{Mg}, \mathrm{Na}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{Ne}, \mathrm{Mg}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & { }_{10} \mathrm{Ne}=1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6,{ }_{11} \mathrm{Na}=1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6 3 \mathrm{~s}^1, \\ & { }_{12} \mathrm{Mg}=1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6 3 \mathrm{~s}^2\end{aligned}\)…
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