AP EAMCET · Chemistry · States of Matter
At \(T(\mathrm{~K})\), the ratio of kinetic energies of \(4 \mathrm{~g}\) of \(\mathrm{H}_2(g)\) and \(8 \mathrm{~g}\) of \(\mathrm{O}_2(g)\) is
- A \(1: 4\)
- B \(4: 1\)
- C \(2: 1\)
- D \(8: 1\)
Answer & Solution
Correct Answer
(D) \(8: 1\)
Step-by-step Solution
Detailed explanation
\(\mathrm{KE}=\frac{3}{2} R T\) for 1 mole of the gas. \(\because 4 \mathrm{~g}\) of \(\mathrm{H}_2\) gas has 2 moles of \(\mathrm{H}_2\) \(\therefore\) It has 2 times KE as compared to 1 mole of gas But \(8 \mathrm{~g}\) of \(\mathrm{O}_2\) gas has \(1 / 4\) moles of…
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