AP EAMCET · Chemistry · Ionic Equilibrium
At \(T(\mathrm{~K})\), if the ionisation constant of ammonia in solution is \(2.5 \times 10^{-5}\), the \(\mathrm{pH}\) of \(0.01 \mathrm{M}\) ammonia solution and the ionisation constant of its conjugate acid respectively at that temperature are \((\log 2=0.30)\)
- A \(10.7,4.0 \times 10^{-8}\)
- B \(10.7,4.0 \times 10^{-10}\)
- C \(3.3,4.0 \times 10^{-8}\)
- D \(3.3,4.0 \times 10^{-10}\)
Answer & Solution
Correct Answer
(B) \(10.7,4.0 \times 10^{-10}\)
Step-by-step Solution
Detailed explanation
\(K_a \times K_b=K_w=10^{-14}\) (at \(25^{\circ} \mathrm{C}\)) where, \(K_a=\) ionisation constant for acid \(\left(\mathrm{NH}_4^{+}\right)\) and \(K_b=\) ionisation constant for base \(\left(\mathrm{NH}_3\right)\) \(=2.5 \times 10^{-5}\) i.e.…
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