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AP EAMCET · Chemistry · Electrochemistry

The \(\mathrm{E}^{\circ}\) of \(\mathrm{M} \mid \mathrm{M}^{2+} \| \mathrm{Cu}^{2+} / \mathrm{Cu}\) is 0.3 V , At what concentration of \(\mathrm{Cu}^{2+}\) (in \(\mathrm{mol} \mathrm{L}^{-1}\) ), the \(\mathrm{E}_{\text {cell }}\) value becomes zero?
\(\left(\frac{2.303 R T}{F}=0.06\right)\left(\text { Conc. of } \mathrm{M}^{2+}=0.1 \mathrm{M}\right)\)

  1. A \(10^{-9}\)
  2. B \(10^{-8}\)
  3. C \(10^{-11}\)
  4. D \(10^{-10}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(10^{-11}\)

Step-by-step Solution

Detailed explanation

According to Nernst equation, \(\mathrm{E}=\mathrm{E}^{\circ}-\frac{2.303 \mathrm{RT}}{\mathrm{nF}} \log \frac{[\text { product }]}{[\text { reactant }]}\)…