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AP EAMCET · Chemistry · p Block Elements (Group 13 & 14)

Assertion \((\mathrm{A})\left[\mathrm{SiF}_6\right]^{2-}\) is formed but \(\left[\mathrm{SiCl}_6\right]^{2-}\) is not
Reason (R) Electronegativity (EN) of \(\mathrm{F}\) is higher than \(\mathrm{EN}\) of \(\mathrm{Cl}\)

  1. A Both (A) and (R) are correct and (R) is the correct explanation of (A)
  2. B Both (A) and (R) are correct but (R) is not the correct explanation of (A)
  3. C (A) is correct but (R) is not correct
  4. D (A) is not correct but (R) is correct
Verified Solution

Answer & Solution

Correct Answer

(B) Both (A) and (R) are correct but (R) is not the correct explanation of (A)

Step-by-step Solution

Detailed explanation

\(\mathrm{SiF}_6^{2-}\) is formed but \(\mathrm{SiCl}_6^{2-}\) is not because \(\mathrm{Cl}\) has greater size than \(\mathrm{F}\). Therefore, larger size of anions cannot form complex with silicon. Electronegativity of \(\mathrm{F}\) is higher than \(\mathrm{Cl}\) but cannot…
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