AP EAMCET · Chemistry · States of Matter
At \(300 \mathrm{~K}\), one mole of a gas present in a \(10 \mathrm{~L}\) flask exerted a pressure of \(2.706 \mathrm{~atm}\).
What is its compressibility factor \((\mathrm{Z})\) ?
(Given \(\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) ).
- A \(1.0\)
- B \(1.5\)
- C \(0.91\)
- D \(1.1\)
Answer & Solution
Correct Answer
(D) \(1.1\)
Step-by-step Solution
Detailed explanation
\(Z=\frac{P V}{R T}=\frac{(2.706)(10)}{(0.082)(300)}=1.1\)
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