AP EAMCET · Maths · Circle
If the point of intersection of the tangents drawn at the points where the line \(5 x+y+1=0\) cuts the circle \(x^2+y^2-2 x-6 y-8=0\) is \((\underline{a, b})\), then \(5 a+b=\)
- A 3
- B -44
- C -1
- D 4
Answer & Solution
Correct Answer
(B) -44
Step-by-step Solution
Detailed explanation
Given circle, \[ x^2+y^2-2 x-6 y-8=0 \] So, chord of contact of two tangents drawn from the point \(P(a, b)\) to the given circle is \[ \begin{gathered} x a+y b-(x+a)-3(y+b)-8=0 \\ \Rightarrow \quad(a-1) x+(b-3) y-(a+3 b+8)=0 \end{gathered} \] As, this line coincides with…
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