AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The set of species having only fractional bond order values is
- A \(\mathrm{C}_2^{2-}, \mathrm{N}_2, \mathrm{O}_2^{2-}\)
- B \(\mathrm{O}_2^{+}, \mathrm{O}_2^{-}, \mathrm{N}_2^{+}\)
- C \(\mathrm{O}_2^{2+}, \mathrm{O}_2, \mathrm{C}_2^{2-}\)
- D \(\mathrm{Li}_2, \mathrm{H}_2^{+}, \mathrm{C}_2\)
Answer & Solution
Correct Answer
(B) \(\mathrm{O}_2^{+}, \mathrm{O}_2^{-}, \mathrm{N}_2^{+}\)
Step-by-step Solution
Detailed explanation
Bond order \((\mathrm{BO})=\frac{1}{2}\) (number of electron in bonding MO's - number of electron in anti-bonding \(\mathrm{MO}^{\prime} \mathrm{s}\) ) \(\mathbf{C}_2^{2-}:\) Total number of electrons \(=6+6+2=14\) Electronic configuration…
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