ExamBro
ExamBro
AP EAMCET · Chemistry · Chemical Equilibrium

At \(1000 \mathrm{~K}\), the equilibrium constant. \(K_C\) for the reaction \(2 \mathrm{NOCl}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{Cl}_2(g)\) is \(4.0 \times 10^{-6} \mathrm{~mol} \mathrm{~L}^{-1}\). The \(K_P\) (in bar) at the same temperature is \(\left(R=0.083 \mathrm{~L} \mathrm{bar} \mathrm{K}^{-1} \mathrm{~mol}^{-1}\right)\)

  1. A \(3.32 \times 10^{-6}\)
  2. B \(3.32 \times 10^4\)
  3. C \(3.32 \times 10^{-4}\)
  4. D \(3.32 \times 10^{-3}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(3.32 \times 10^{-4}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \text { Given, } K_C=4 \times 10^{-6} \mathrm{~mol} / \mathrm{L} \\ & \quad 2 \mathrm{NOCl}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{Cl}_2(g) \\ & \Delta n=\text { product mole }- \text { reactant mole } \\ & =3-2=1\end{aligned}\)