AP EAMCET · Maths · Circle
If \((4,7)\) and \((-2,-1)\) are ends of a diameter of a circle which intersects \(X\)-axis at \(A\) and \(B\), then \(A B\) is equal to
- A 5
- B 6
- C 7
- D 8
Answer & Solution
Correct Answer
(D) 8
Step-by-step Solution
Detailed explanation
End points of diameter are \((4,7)\) and \((-2,-1)\). Then, equation of circle is \[ \begin{aligned} & (x-4)(x+2)+(y-7)(y+1)=0 \\ & \Rightarrow \quad x^2+y^2-2 x-6 y-15=0 \end{aligned} \] General equation of circle is \[ x^2+y^2+2 g x+2 f y+c=0 \] Compare Eqs. (i) and (ii), we…
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