AP EAMCET · Chemistry · Hydrogen
Arrange the hydrides \(\mathrm{NH}_3, \mathrm{HF}, \mathrm{H}_2 \mathrm{O}, \mathrm{HCl}\) in the increasing order of their boiling points
- A \(\mathrm{HF} < \mathrm{NH}_3 < \mathrm{HCl} < \mathrm{H}_2 \mathrm{O}\)
- B \(\mathrm{H}_2 \mathrm{O} < \mathrm{HF} < \mathrm{HCl} < \mathrm{NH}_3\)
- C \(\mathrm{NH}_3 < \mathrm{HCl} < \mathrm{H}_2 \mathrm{O} < \mathrm{HF}\)
- D \(\mathrm{HCl} < \mathrm{NH}_3 < \mathrm{HF} < \mathrm{H}_2 \mathrm{O}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{HCl} < \mathrm{NH}_3 < \mathrm{HF} < \mathrm{H}_2 \mathrm{O}\)
Step-by-step Solution
Detailed explanation
(d\(\mathrm{H}_2 \mathrm{O}\), HF and \(\mathrm{NH}_3\) have hydrogen bonding as the intermolecular forces while \(\mathrm{HCl}\) has weaker dipoledipole interaction. Thus, \(\mathrm{HCl}\) has the lowest boiling point. Among \(\mathrm{H}_2 \mathrm{O}\), HF, and…
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