AP EAMCET · Chemistry · Chemical Kinetics
In a first order reaction, the concentration of the reactant is reduced from \(0.6 \mathrm{~mol} \mathrm{~L}^{-1}\) to \(0.2 \mathrm{~mol} \mathrm{~L}^{-1}\) in \(5 \mathrm{~min}\). What is the rate constant of the reaction? \((\log 3=0.4771)\)
- A \(0.219 \mathrm{~min}^{-1}\)
- B \(0.325 \mathrm{~min}^{-1}\)
- C \(0.421 \mathrm{~min}^{-1}\)
- D \(0.522 \mathrm{~min}^{-1}\)
Answer & Solution
Correct Answer
(A) \(0.219 \mathrm{~min}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, \[ \begin{aligned} t & =5 \text { minute } \\ A^{\circ} & =0.6 \mathrm{~mol}^{-1} \\ A & =0.2 \mathrm{~mol}^{-1} \\ k & =\frac{2.303}{t} \log \frac{A^{\circ}}{A} \\ & =\frac{2.303}{5} \log \frac{0.6}{0.2}=0.219 \mathrm{~min}^{-1} \end{aligned} \]
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