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JEE Mains · Maths · STD 11 - 7. binomial theoram

यदि \(\left(\sqrt{ x }-\frac{ k }{ x ^{2}}\right)^{10}\) के द्विपद प्रसार में अचर में पद \(405\) , है तो \(| k |\) बराबर है 

  1. A \(2\)
  2. B \(1\)
  3. C \(3\)
  4. D \(9\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(3\)

Step-by-step Solution

Detailed explanation

\(\left(\sqrt{x}-\frac{k}{x^{2}}\right)^{10}\) \(T_{r+1}={ }^{10} C_{r}(\sqrt{x})^{10-r}\left(\frac{-k}{x^{2}}\right)^{r}\) \(T_{r+1}={ }^{10} C_{r} \cdot x^{\frac{10-r}{2}} \cdot(-k)^{r} \cdot x^{-2 r}\) \(T_{r+1}={ }^{10} C_{r} x^{\frac{10-5 r}{2}}(-k)^{r}\) Constant term…
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