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JEE Mains · Maths · STD 12 - 11. three dimension geometry

यदि रेखाओं \(\frac{x}{2}=\frac{y}{2}=\frac{z}{1}\) तथा \(\frac{5-x}{-2}=\frac{7 y-14}{ P }=\frac{z-3}{4}\) के बीच का कोण \(\cos ^{-1}\left(\frac{2}{3}\right)\) है, तो \(p\) बराबर है

  1. A \( - \frac{7}{4}\)
  2. B \(\frac{2}{7}\)
  3. C \( - \frac{4}{7}\)
  4. D \(\frac{7}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{7}{2}\)

Step-by-step Solution

Detailed explanation

Let \(\theta\) be the angle between the two lines Here direction cosines of \(\frac{x}{2}=\frac{y}{2}=\frac{z}{1}\) are \(2,2,1\) Also second line can be written as: \(\frac{{\frac{{x - 5}}{2} = \frac{{y - 2}}{P} = \frac{{ - 3}}{4}}}{7}\) \(\therefore \) its direction cosines…
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