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JEE Mains · Maths · STD 11 - Trigonometrical equations

यदि \(0 \le x \le \pi \) तब \({81^{{{\sin }^2}x}} + {81^{{{\cos }^2}x}} = 30\) है, तो \(x\) का मान है

  1. A \(\pi /6\)
  2. B \(\pi /2\)
  3. C \(\pi /4\)
  4. D \(3\pi /4\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\pi /6\)

Step-by-step Solution

Detailed explanation

ज्ञात है, \({81^{{{\sin }^2}x}} + {81^{{{\cos }^2}x}} = 30\) विकल्पों का निरीक्षण करने के बाद \(x = \frac{\pi }{6}\) रखने पर, \({(81)^{{{\sin }^2}\pi /6}} + {(81)^{{{\cos }^2}\pi /6}} = 30\) \(\Rightarrow\) \({(81)^{1/4}} + {(81)^{3/4}} = 30\) अत: विकल्प \((a)\) सही है।
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