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JEE Mains · Maths · STD 11 - 8. sequence and series

माना श्रेणी \(1^{2}+2 \cdot 2^{2}+3^{2}+2 \cdot 4^{2}+5^{2}+2 \cdot 6^{2}+\ldots .\) के प्रथम \(20\) पदों का योग \(A\) है तथा प्रथम \(40\) पदों का योग \(B\) है। यदि \(B-2 A=100 \lambda .\) तो \(\lambda\) बराबर है

  1. A \(248\)
  2. B \(464\)
  3. C \(496\)
  4. D \(232\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(248\)

Step-by-step Solution

Detailed explanation

(1) Here, \(B - 2A = \) \(\sum\limits_{n = 1}^{40} {{a_n} - 2\sum\limits_{n = 1}^{20} {{a_n}} } = \sum\limits_{n = 21}^{40} {{a_n} - 2\sum\limits_{n = 1}^{20} {{a_n}} } \)…
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