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JEE Mains · Maths · STD 11 - 8. sequence and series

माना \(\left\langle a_{\mathrm{n}}\right\rangle\) एक अनुक्रम है इस प्रकार कि \(a_0=0, a_1=\frac{1}{2}\) और \(2 a_{\mathrm{n}+2}=5 a_{\mathrm{n}+1}-3 a_{\mathrm{n}}, \mathrm{n}=0,1,2,3, \ldots\) है। तो \(\sum_{\mathrm{k}=1}^{100} a_k\) = __________

  1. A \(3 \mathrm{a}_{99}-100\)
  2. B \(3 \mathrm{a}_{100}-100\)
  3. C \(3 \mathrm{a}_{99}+100\)
  4. D \(3 \mathrm{a}_{100}+100\)
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Answer & Solution

Correct Answer

(B) \(3 \mathrm{a}_{100}-100\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & a_0=0, a_1=\frac{1}{2} \\ & 2 a_{n+2}=5 a_{n+1}-3 a_n \\ & 2 x^2-5 x+3=0 \Rightarrow x=1,3 / 2 \\ & \therefore a_n=A l^n+B\left(\frac{3}{2}\right)^n\end{aligned}\)…
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