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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

\(\frac{1}{2} \mathrm{Cl}_2(\mathrm{~g})\) से \(\mathrm{Cl}^{-}(\mathrm{aq})\) में रूपांतरण के लिए एंथेल्पी परिवर्तन है (-) ____________ \(\mathrm{kJ} \mathrm{mol}^{-1}\) (निकटतम पूर्णांक में) दिया है : \(\Delta_{\mathrm{dis}} \mathrm{H}_{\mathrm{Cl}_{2(\mathrm{~g})}}^{\mathrm{o}}=240 \mathrm{kJmol}^{-1}\). \(\Delta_{ eg } H _{ Cl _{(g)}}^{\circ}=-350\,kJ\,mol ^{-1}\), \(\Delta_{ hyd } H _{ Cl i _{( j )}^{\circ}}^{\circ}=-380\,kJ\,mol ^{-1}\)

  1. A \(600\)
  2. B \(620\)
  3. C \(630\)
  4. D \(610\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(610\)

Step-by-step Solution

Detailed explanation

\(\frac{1}{2} Cl _{2( g )} \rightarrow Cl _{( g )} \rightarrow Cl _{( g )}^{-} \rightarrow Cl _{( aq .)}^{-}\) \(\Delta H ^{\circ}=\frac{1}{2} \times 240+(-350)+(-380)\) \(=-610 \text { ans. }\)
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