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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

\(xyz\) ના ગુણાકારની ન્યૂનતમ કિમત મેળવો કે જેથી \(\left| {\begin{array}{*{20}{c}}
  x&1&1 \\ 
  1&y&1 \\ 
  1&1&z 
\end{array}} \right|\) ની કિમંત અનૃણ મળે.

  1. A \(-2\sqrt 2\)
  2. B \(-1\)
  3. C \(-16\sqrt 2\)
  4. D \(-8\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(-8\)

Step-by-step Solution

Detailed explanation

\(\begin{array}{*{20}{c}} x&1&1\\ 1&y&1\\ 1&1&z \end{array} \ge 0\) \(xyz - x - y - z + 2 \ge 0\) \(xyz + 2 \ge x + y + z \ge 3{\left( {xyz} \right)^{1/3}}\) \(xyz + 2 - 3{\left( {xyz} \right)^{1/3}} \ge 0\) at \(\left( {xyz} \right) = {t^3}\) \({t^3} - 3t + 2 \ge 0\)…
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