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JEE Mains · Maths · STD 12 - 7.2 definite integral

\(\lim _{x \rightarrow 0} \frac{\int_{0}^{x^{2}}(\sin \sqrt{t}) dt }{x^{3}}\) \(=...........\)

  1. A \(\frac{2}{3}\)
  2. B \(\frac{2}{3}\)
  3. C \(0\)
  4. D \(\frac{1}{15}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{2}{3}\)

Step-by-step Solution

Detailed explanation

\(\lim _{x \rightarrow 0^{+}} \frac{\int_{0}^{x^{2}} \sin \sqrt{t} d t}{x^{3}}=\lim _{x \rightarrow 0^{+}} \frac{(\sin x) 2 x}{3 x^{2}}\) \(=\lim _{x \rightarrow 0^{+}}\left(\frac{\sin x}{x}\right) \times \frac{2}{3}=\frac{2}{3}\)
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