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JEE Mains · Maths · STD 11- 2. Relation and Function

જો વિધેય \(f(x)=\frac{[x]}{1+x^2}\) નો પ્રદેશ \([2,6)\) હોય, તો તેનો વિસ્તાર \(............\) છે.

  1. A \(\left(\frac{5}{26}, \frac{2}{5}\right]-\left\{\frac{9}{29}, \frac{27}{109}, \frac{18}{89}, \frac{9}{53}\right\}\)
  2. B \(\left(\frac{5}{26}, \frac{2}{5}\right]\)
  3. C \(\left(\frac{5}{37}, \frac{2}{5}\right]-\left\{\frac{9}{29}, \frac{27}{109}, \frac{18}{89}, \frac{9}{53}\right\}\)
  4. D \(\left(\frac{5}{37}, \frac{2}{5}\right]\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\left(\frac{5}{37}, \frac{2}{5}\right]\)

Step-by-step Solution

Detailed explanation

\(\begin{array}{ll}f(x)=\frac{2}{1+x^2} & x \in[2,3) \\ f(x)=\frac{3}{1+x^2} & x \in[3,4) \\ f(x)=\frac{4}{1+x^2} & x \in[4,5) \\ f(x)=\frac{5}{1+x^2} & x \in[5,6)\end{array}\) \(\left(\frac{5}{37}, \frac{2}{5}\right]\)
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