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JEE Mains · Maths · STD 11 - 8. sequence and series

જો શ્રેણી \({\left( {\frac{3}{4}} \right)^3} + {\left( {1\frac{1}{2}} \right)^3} + {\left( {2\frac{1}{4}} \right)^3} + {3^3} + {\left( {3\frac{3}{4}} \right)^3} + .....\)  ના પ્રથમ \(15\) પદોનો સરવાળો \(225\,k\) થાય તો \(k\) ની કિમત મેળવો. 

  1. A \(108\)
  2. B \(27\)
  3. C \(54\)
  4. D \(9\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(27\)

Step-by-step Solution

Detailed explanation

\(S = {\left( {\frac{3}{4}} \right)^3} + {\left( {\frac{6}{4}} \right)^3} + {\left( {\frac{9}{4}} \right)^3} + {\left( {\frac{{12}}{4}} \right)^3} + ........15\,term\) \( = \frac{{27}}{{64}}\sum\limits_{r = 1}^{15} {{r^3}} \)…
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