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JEE Mains · Maths · STD 12 - 11. three dimension geometry

જો રેખાઓ \(L _1: \frac{x-1}{3}=\frac{y-2}{4}=\frac{z-a}{b}\) તથા \(L _2: \frac{x-1}{1}=\frac{y-2}{4}=\frac{z-a}{c}\) ની દિશામાં, બિંદુ (1, 2 ,a) ના રેખા \(\frac{x-1}{1}=\frac{y}{2}=\frac{z-1}{1}\) થી અંતરો સમાન હોય, તો a + b + c = ___ .

  1. A 7
  2. B 5
  3. C 6
  4. D 4
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Answer & Solution

Correct Answer

(A) 7

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Detailed explanation

\begin{aligned} & \mathrm{L}: \frac{\mathrm{x}-1}{1}=\frac{\mathrm{y}}{2}=\frac{\mathrm{z}-1}{1} \\ & \mathrm{~L}_1: \frac{\mathrm{x}-1}{3}=\frac{\mathrm{y}-2}{4}=\frac{\mathrm{z}-\mathrm{a}}{\mathrm{b}}=\lambda \\ & \mathrm{L}_2:…

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