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JEE Mains · Maths · STD 12 - 1. relation and function

ધારોકે f અને g એ પ્રત્યેક \(x, y \in N\) માટે \(f(x+y)=f(x) f(y), f(1)=7\) અને \(g(x+y)=g(x y), g(1)=1\) નું સમાધાન કરતાં વિધેયો છે. જો \(\sum_{x=1}^{ n }\left(\frac{f(x)}{ g (x)}\right)=19607\) હોય, તો \(n =\) ___ .

  1. A 7
  2. B 5
  3. C 6
  4. D 4
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Correct Answer

(B) 5

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Detailed explanation

\(f(x+y)=f(x) \cdot f(y) \Rightarrow f(x)=a^x\) \(\left(\because f(1)=7 \Rightarrow=a^1=7\right)\) So \(f(x)=7^x\) Now \(g(x+y)=g(x y) \quad(\text { put } y=1)\) \(\Rightarrow g ( x +1)= g ( x )\) so \(g (1)= g (2)= g (3)=\ldots= g ( n )=1\) Given…
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