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JEE Mains · Maths · STD 12 - 10. vector algebra

\(\vec a = 2\hat i + \hat j - 2\hat k,\vec b = \hat i + \hat j\) આપલે છે. જો સદીશ \(\vec c\) આપેલ છે કે જેથી  \(\vec a.\vec c = \left| {\vec c} \right|,\left| {\vec c - \vec a} \right| = 2\sqrt 2 \) અને \(\vec a \times \vec b\) અને  \(\vec c\) વચ્ચેનો ખૂણો  \(30^o\) હોય તો  \(\left| {\left( {\vec a \times \vec b} \right) \times \vec c} \right|\) મેળવો.

  1. A \(\frac{1}{2}\)
  2. B \(\frac{{3\sqrt 3 }}{2}\)
  3. C \(3\)
  4. D \(\frac{3}{2}\)
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Correct Answer

(D) \(\frac{3}{2}\)

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Detailed explanation

\({\vec{a}=2 \hat{i}+\hat{j}-2 \hat{k}, \vec{b}=\hat{i}+\hat{j}}\) \({\Rightarrow|\vec{a}|=3}\) and \(\vec a \times \vec b = \begin{array}{*{20}{c}} {\hat i}&{\hat j}&{\hat k}\\ 2&1&{ - 2}\\ 1&1&0 \end{array} = 2\hat i - 2\hat j + \hat k\)…
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