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JEE Mains · Maths · STD 11 - 7. binomial theoram

\({\left( {{2^{\frac{1}{2}}} + {3^{\frac{1}{5}}}} \right)^{10}}\) ના વિસ્તરણમાં રહેલા સંમેય પદોનો સરવાળો મેળવો.

  1. A \(25\)
  2. B \(32\)
  3. C \(9\)
  4. D \(41\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(41\)

Step-by-step Solution

Detailed explanation

\(\left(2^{1 / 2}+3^{1 / 5}\right)^{10}=^{10} \mathrm{C}_{0}\left(2^{1 / 2}\right)^{10}\) \(+^{10} \mathrm{C}_{1}\left(2^{1 / 2}\right)^{9}\left(3^{1 / 5}\right)+\ldots \ldots+^{10} \mathrm{C}_{10}\left(3^{1 / 5}\right)^{10}\) There are onlytwo rational terms - first term and…
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