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WBJEE · Physics · Oscillations

Two simple harmonic motions are given by \(x_{1}=a \sin \omega t+a \cos \omega t\) and \(x_{2}=a \sin \omega t+\frac{a}{\sqrt{3}} \cos \omega t\) The ratio of the amplitudes of first and second motion and the phase difference between them are respectively

  1. A \(\sqrt{\frac{3}{2}}\) and \(\frac{\pi}{12}\)
  2. B \(\frac{\sqrt{3}}{2}\) and \(\frac{\pi}{12}\)
  3. C \(\frac{2}{\sqrt{3}}\) and \(\frac{\pi}{12}\)
  4. D \(\sqrt{\frac{3}{2}}\) and \(\frac{\pi}{6}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\sqrt{\frac{3}{2}}\) and \(\frac{\pi}{12}\)

Step-by-step Solution

Detailed explanation

The given situation can be shown as Fon second SHM Ratio of amplitude \(=\frac{a_{1}}{a_{2}}=\frac{\sqrt{3}}{\sqrt{2}}\) and phase difference, \(\frac{\pi}{4}-\frac{\pi}{6}=\frac{\pi}{12}\)