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WBJEE · Physics · Oscillations

What is the phase difference between two simple harmonic motions represented by \(x_{1}=A \sin \left(\omega t+\frac{\pi}{6}\right)\) and \(x_{2}=A \cos (\omega t) ?\)

  1. A \(\frac{\pi}{6}\)
  2. B \(\frac{\pi}{3}\)
  3. C \(\frac{\pi}{2}\)
  4. D \(\frac{2 \pi}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{\pi}{3}\)

Step-by-step Solution

Detailed explanation

Given, \[ \begin{array}{l} x_{1}=A \sin \left(\omega t+\frac{\pi}{6}\right) \\ x_{2}=A \cos (\omega t) \\ x_{2}=A \operatorname{sin}\left(\omega t+\frac{\pi}{2}\right) \end{array} \] Phase difference \[ \Delta \phi=\phi_{2}-\phi_{1} \]…