WBJEE · Physics · Dual Nature of Matter
The de-Broglie wavelength of an electron moving with a velocity \(c / 2\) ( \(c=\) velocity of light in vacuum) is equal to the wavelength of a photon. The ratio of the kinetic energies of electron and photon is
- A \(1: 4\)
- B \(1: 2\)
- C \(1: 1\)
- D \(2: 1\)
Answer & Solution
Correct Answer
(B) \(1: 2\)
Step-by-step Solution
Detailed explanation
de-Broglie wavelength \[ \lambda=\frac{h}{m v} \] Here, \(\lambda_{e}=\frac{h}{m_{e} \frac{c}{2}}\) and \(\lambda_{p}=\frac{h}{m_{p} c}\) Given, \(\quad \lambda_{e}=\lambda_{B}\) So, \(\quad \frac{h}{m_{e} \frac{c}{2}}=\frac{h}{m_{p} c}\) \(\frac{m_{e}}{m_{p}}=2\) Ratio of KE…
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