WBJEE · Physics · Center of Mass Momentum and Collision
A shell of mass \(5 M\), acted upon by no external force and initially at rest, bursts into three fragments of masses \(M, 2 M\) and \(2 M\) respectively. The first two fragments move in opposite directions with velocities of magnitudes 2v and \(v\) respectively. The third fragment will
- A move with a velocily \(v\) in a direction perpendicular To the other two
- B move with a velocity \(2 v\) in the direction of velocity of the first fragment
- C be at rest
- D move with velocity \(v\) in the direction of velocity of the second fragment
Answer & Solution
Correct Answer
(C) be at rest
Step-by-step Solution
Detailed explanation
Let the velocity of third fragment is \(v'\). Then by the conservation of linear momentum \[ \begin{aligned} & 5(0)=M \times 2 \mathrm{v}-2 M \times \mathrm{v}+2 \mathrm{M} \times \mathrm{v}^{\prime} \\ \Rightarrow \quad & \mathrm{v}^{\prime}=0 \end{aligned} \] i.e., the third…
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