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WBJEE · Maths · Functions

If \(f(x)\) is an odd differentiable function defined on \((-\infty, \infty)\) such that \(f^{\prime}(3)=2,\) then \(f^{\prime}(-3)\) is equal to

  1. A 0
  2. B 1
  3. C 2
  4. D 4
Verified Solution

Answer & Solution

Correct Answer

(C) 2

Step-by-step Solution

Detailed explanation

Given that \(f(x)\) is an odd differentiable function. Then, \(f(-x)=-f(x)\) \(\begin{array}{lr}\Rightarrow & -f^{\prime}(-x)=-f^{\prime}(x) \\ \Rightarrow & f^{\prime}(-x)=f^{\prime}(x)\end{array}\) Put \(x=3\) in Eq. (i), we get \(\therefore\)…