WBJEE · Chemistry · States of Matter
At a certain temperature the time required for the complete diffusion of \(200 \mathrm{mL}\) of \(\mathrm{H}_{2}\) gas is 30 min. The time required for the complete diffusion of \(50 \mathrm{mL}\) of \(\mathrm{O}_{2}\) gas at the same temperature will be
- A \(60 \mathrm{min}\)
- B \(30 \mathrm{min}\)
- C \(45 \mathrm{min}\)
- D \(15 \mathrm{min}\)
Answer & Solution
Correct Answer
(B) \(30 \mathrm{min}\)
Step-by-step Solution
Detailed explanation
According to Graham's law of diffusion. Rate of diffusion, \(r \propto \frac{1}{\sqrt{M}}=\frac{V}{t}\) Here, \(M=\) molecular mass, \(V=\) volume and \(t=\) timel Thus, for \(\mathrm{H}_{2}\) gas, \[ \frac{200}{30}=\frac{1}{\sqrt{2}} \] for \(O_{2}\) gas,…
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