WBJEE · Physics · Nuclear Physics
For nuclei with mass number close to 119 and 238 , the binding energies per nucleon are approximately \(7.6 \mathrm{MeV}\) and \(8.6 \mathrm{MeV}\) respectively. If a nucleus of mass number 238 breaks into two nuclei of nearly equal masses, what will be the approximate amount of energy released in the process of fission?
- A \(214 \mathrm{MeV}\)
- B \(119 \mathrm{MeV}\)
- C \(2047 \mathrm{MeV}\)
- D \(1142 \mathrm{MeV}\)
Answer & Solution
Correct Answer
(A) \(214 \mathrm{MeV}\)
Step-by-step Solution
Detailed explanation
Hint: \(119 \rightarrow 7.6 \mathrm{MeV}\) \(238 \rightarrow 8.6 \mathrm{MeV}\) \(238 \rightarrow 119+119\) \(E_{1}=238 \times 8.6\) \(E_{t}=238 \times 7.6\) \(\therefore E_{t}-E_{1}=-238 \mathrm{MeV}\) Anegative value indicates the fission cannot take place. The data given are…
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