WBJEE · Physics · Thermodynamics
Consider a thermodynamic process where internal energy \(U=A P^2 \mathrm{~V}(\mathrm{~A}=\) constant). If the process is performed adiabatically, then
- A \(A P^2(V+1)=\) constant
- B \((\mathrm{AP}+1)^2 \mathrm{~V}=\mathrm{constant}\)
- C \((\mathrm{AP}+1) \mathrm{V}^2=\) constant
- D \(\frac{V}{(A P+1)^2}=\) constant
Answer & Solution
Correct Answer
(B) \((\mathrm{AP}+1)^2 \mathrm{~V}=\mathrm{constant}\)
Step-by-step Solution
Detailed explanation
\(U=A P^2 V\) \(\frac{d U}{d V}=A P^2+2 P A V \frac{d P}{d V}\) [For adiabatic process \(\left.d Q=0, d U=-d w=-P d V\right]\) \(-\frac{P d V}{d V}=A P^2+2 P A V \frac{d P}{d V}\) \(-1=A P+2 A V \frac{d P}{d V} \Rightarrow-1-A P=2 A V \frac{d P}{d V}\)…
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