WBJEE · Physics · Nuclear Physics
An alpha particle \(\left({ }^{4} \mathrm{He}\right)\) has a mass of 4.00300 amu. A proton has a mass of 1.00783 amu and a neutron has a mass of 1.00867 amu respectively. The binding energy of alpha estimated from these data is the closest to
- A \(27.9 \mathrm{MeV}\)
- B \(22.3 \mathrm{MeV}\)
- C \(35.0 \mathrm{MeV}\)
- D \(20.4 \mathrm{MeV}\)
Answer & Solution
Correct Answer
(A) \(27.9 \mathrm{MeV}\)
Step-by-step Solution
Detailed explanation
The mass defect, \(\Delta m=2\left(m_{p}+m_{n}\right)-m_{\text {He }}\) \(=2(1.00783+1.00867)-4.00300\) \(=0.0300\) amu So, the binding energy, \(E=\Delta m c^{2}\) \(=0.03 \times 931 \mathrm{MeV}=27.9 \mathrm{MeV}\)
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