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WBJEE · Physics · Laws of Motion

A smooth massless string passes over a smooth fixed pulley. Two masses \(m_{1}\) and \(m_{2},\left(m_{1}>m_{2}\right)\) are tied at the two ends of the string. The masses are allowed to move under gravity starting from rest. The total external force acting on the two masses is

  1. A \(\left(m_{1}+m_{2}\right) g\)
  2. B \(\frac{\left(m_{1}-m_{2}\right)^{2}}{m_{1}+m_{2}} g\)
  3. C \(\left(m_{1}-m_{2}\right) g\)
  4. D \(\frac{\left(m_{1}+m_{2}\right)^{2}}{m_{1}-m_{2}} g\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{\left(m_{1}-m_{2}\right)^{2}}{m_{1}+m_{2}} g\)

Step-by-step Solution

Detailed explanation

We know that Acceleration, \(a_{\mathrm{CM}}=\left(\frac{m_{1}-m_{2}}{m_{1}+m_{2}}\right)^{2} \times g\left(\because m_{1}>m_{2}\right)\) So, resultant external force.…