WBJEE · Physics · Magnetic Effects of Current
A particle with charge \(q\) moves with a velocity \(v\) in a direction perpendicular to the directions of uniform clectric and magnetic ficlds, \(E\) and \(B\) respectively, which are mutually perpendicular to each other. Which one of the following gives the condition for which the particle moves undeflected in its original trajectory? 
- A \(v=\frac{E}{B}\)
- B \(v=\frac{B}{E}\)
- C \(v=\sqrt{\frac{E}{B}}\)
- D \(v=q \frac{B}{E}\)
Answer & Solution
Correct Answer
(A) \(v=\frac{E}{B}\)
Step-by-step Solution
Detailed explanation
According to the question, Charge on particle is \(=q\) Velocity of particle \(=v\) Due to uniform electric field, electric force on particle \(F_{\text {electric }}=q E\) Due to a uniform magnetic field, magnetic force on particle is given by,…
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